Question

Find the tempature of 1.50 mol of gas whose pressure is 4.00 atm and whose volume is 7.50 L

Answer 1

To find the temperature of the gas we can use the ideal gas law:

`PV=nRT`

where P is the pressure, V is the volume, n is the number of moles of the gas, R is the unirversal gas constant (0.08205746 L atm/ mol K) and T is the temperature.

Plugging the values given into the equation we have:

`\begin{gathered} (4)(7.5)=(1.5)(0.08205746)T \\ T=((4)(7.5))/((1.5)(0.08205746)) \\ T=243.73 \end{gathered}`

Therefore the temperature is 243.73 K