Question

Number 6 Find the limit and use the x values : -0.03, -0.02,-0.01,0,0.01,0.02,0.03

Answer 1

`\begin{gathered} \text{when x=-0.03} \\ (e^(-0.03)-1)/(-0.03)=0.985 \\ \text{when x=-0.02} \\ (e^(-0.02)-1)/(-0.02)=0.99 \\ \text{when x=-0.01} \\ (e^(-0.01)-1)/(-0.01)=0.995 \\ \text{when x=0.01} \\ (e^(0.01)-1)/(0.01)=1.005 \\ \text{when x=0.02} \\ (e^(0.02)-1)/(0.02)=1.01 \\ \text{when x=0.03} \\ (e^(0.03)-1)/(0.03)=1.015 \\ hence,\text{ } \\ \lim _(x\to0)(e^x-1)/(x)=1 \end{gathered}`