Answer:
= : Displacement from t = 0 s to t = 5s
A: Displacement from t = 0 s to t = 2.5s
B: Displacement from t = 2.5 s to t = 5s
= : Average velocity from t = 0 s to t = 5s
A : Average velocity from t = 0 s to t = 2.5s
B: Instantaneous velocity at t = 5s
Step-by-step explanation:
The displacement is the difference between the final and the initial position.
Since at t = 0 and t = 5, A and B have the same position, the displacement was equal. So, the first answer is
= : Displacement from t = 0 s to t = 5s
In the same way, we can see that at t = 2.5 the position of A is greater than the position of B, so from t = 0 to t = 2.5, A has a greater difference of position but from t = 2.5 to t = 5, B has a greater difference of position. Then:
A: Displacement from t = 0 s to t = 2.5s
B: Displacement from t = 2.5 s to t = 5s
The average velocity is equal to the displacement divided by the time. if the time is equal, the average velocity will be greater if the displacement is greater. So:
= : Average velocity from t = 0 s to t = 5s
A : Average velocity from t = 0 s to t = 2.5s
Finally, the instantaneous velocity is the slope of the graph at t = 5. The greater the slope, the greater the velocity. Since the slope of B is greater than the slope of A at t = 5, we can say that B has a greater instantaneous velocity at t =5, so:
B: Instantaneous velocity at t = 5s
So, the answers are:
= : Displacement from t = 0 s to t = 5s
A: Displacement from t = 0 s to t = 2.5s
B: Displacement from t = 2.5 s to t = 5s
= : Average velocity from t = 0 s to t = 5s
A : Average velocity from t = 0 s to t = 2.5s
B: Instantaneous velocity at t = 5s