Question

EVALUATE THE FOLLOWING:A) 85!/82!B) nC0C) nPnI GOT THIS AS MY ANSWER?A.592620B. 1C. 1Part C

Answer 1

To answer this question we need to remember that:

`0!=1`

and that a permutation is defined as:

`_nP_k=(n!)/((n-k)!)`

Then, in this case we have:

`_nP_n=(n!)/((n-n)!)=(n!)/(0!)=(n!)/(1)=n!`

Therefore, we have that:

`_nP_n=n!`