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Can the relationship in Monday’s table be described by a constant unit rate? ExplainCan the relationship in Tuesday’s table be described by a constant unit rate? Explain

Can the relationship in Monday’s table be described by a constant unit rate? ExplainCan-example-1
User Dylanjha
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1 Answer

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Step 1

We will consider the Time(min) and distance (km) covered by Ken on his bike on Monday from the table given

From the Monday table

1) The time increases by a constant unit of 20 mins as seen below


\begin{gathered} 40\text{ -20 = 20 mins} \\ 60-40\text{ = 20 mins} \\ 80-60=\text{ 20 mins} \\ 100\text{ -80 = 20 mins} \end{gathered}

2) The distance however, does not increase by a constant unit as seen below


\begin{gathered} 10\text{ - 5= 5km} \\ 12-\text{ 10= 2 km} \\ 14-12\text{ = 2km} \\ 16-14=\text{ 2km} \end{gathered}

Therefore, the relationship in Monday's table cannot be described by a constant unit rate since the time and distance individually do not increase by a constant unit.

Step 2

From Tuesday's table, we can deduce that

1) The time increases by a constant unit of 20 mins


\begin{gathered} 40\text{ -20 = 20 mins} \\ 60-40\text{ = 20 mins} \\ 80-60=\text{ 20 mins} \\ 100\text{ -80 = 20 mins} \end{gathered}

2) The distance increases by a constant unit of 4km as seen below


\begin{gathered} 8-4=4\operatorname{km} \\ 12-8=4\operatorname{km} \\ 16-12=4\operatorname{km} \\ 20-16=\text{ 4km} \end{gathered}

Since, both the time and distance individually increases by a constant unit, we can therefore conclude that the relationship in Tuesday's table can be described by a constant unit rate.

User PhilHarvey
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