Question

if the perimeter of a rectangle measures 50 feet and the length of the rectangle is 17 feet, what is the width

Answer 1

`\begin{gathered} \text{Perimeter}=2(\text{length}+\text{width)} \\ 50=2(17+\text{width)} \\ 17+\text{width}=(50)/(2) \\ \text{width}=25-17 \\ \text{width}=8\text{feet} \end{gathered}`