Final answer:
The molar mass of chromium(II) nitrate, Cr(NO₃)₂, is calculated by summing the atomic masses of one Cr atom, two N atoms, and six O atoms, resulting in a molar mass of 175.004 g/mol.
Step-by-step explanation:
To determine the molar mass of chromium(II) nitrate, Cr(NO3)2, we must first calculate the mass of each element present in one mole of the compound and then sum these values.
Identify the atomic masses of the individual elements (Cr, N, O) from the periodic table.
Multiply the atomic masses with the number of atoms in the formula. Chromium has one atom, nitrogen has two atoms, since there are two nitrate groups, and oxygen has six atoms because each nitrate group contains three oxygen atoms.
Add all the atomic masses together to obtain the molar mass of Cr(NO₃)₂.
For chromium (Cr), the atomic mass is approximately 51.996 g/mol. Nitrogen (N) has an atomic mass of approximately 14.007 g/mol, and oxygen (O) has an atomic mass of about 15.999 g/mol. Including the respective number of atoms:
1x51.996 g/mol Cr + 2x14.007 g/mol N + 6x15.999 g/mol O = Molar mass of Cr(NO₃)₂
Now, adding these together:
51.996 + (2x14.007) + (6x15.999) = 51.996 + 28.014 + 95.994 = 175.004 g/mol
Therefore, the molar mass of Cr(NO₃)₂ is 175.004 g/mol.