Question

If you have 1 points spread out randomly so that no 3 points are colinear, how many lines can you draw using 2 points? (Hint start at 1 dot and connect lines as you add each dot, you might notice a pattern)

Answer 1

Given that;

If you have 1 point spread out randomly, so that no 3 points are colinear

Colinear points are points that lines on the same line.

Drawing points randomly from the given 3 points

Applying the combination formula,

`\begin{gathered} nCr=(n!)/(\left(n-r\right)!r!) \\ Where \\ n=3 \\ r=2 \\ 3C2=(3!)/(2!(3-2)!)=(3!)/(2!1!)=(3*2*1)/(2*1*1)=3 \end{gathered}`

Hence, the number of lines you can draw is 3