Question

Two capacitors of 4 μF and 8 μF are connected in parallel. What is the equivalent capacitance of this system?3 μF17 μF12 μF9 μF

Answer 1

`12\mu F`

Step-by-step explanation

The equivalent capacitance of two capacitors connected in parallel is the sum of the individual capacitances.

`C_(eq)=C_1+C_2`

Step 1

Let

`\begin{gathered} C_1=4\mu F \\ C_2=8\mu F \end{gathered}`

hence

`\begin{gathered} C_(eq)=C_1+C_2 \\ C_(eq)=4\mu F+8\mu F \\ C_(eq)=12\mu F \end{gathered}`

therefore, the answer is

`12\mu F`

I hope this helps you