Question

I would like a quick answer since I'm in a hurry

Answer 1

- The solution steps are given below:

`\begin{gathered} 6x^4+2x^3-4x^2+2 \\ p\text{ is the set of all the factors of the constant term.} \\ p=\pm1,\pm2 \\ \\ q\text{ is the set of all the factors of the leading term} \\ q=\pm1,\pm2,\pm3,\pm6 \\ \\ \text{ Thus, the potential zeros are:} \\ (p)/(q)=(1)/(1),-(1)/(1),(1)/(2),-(1)/(2),(1)/(3),-(1)/(3),(1)/(6),-(1)/(6),(2)/(1),-(2)/(1),(2)/(3),-(2)/(3) \\ \\ \text{ Thus, this set of potential zeros is given as:} \\ (p)/(q)=\lbrace\pm(1)/(6),\pm(1)/(3),\pm(1)/(2),\pm(2)/(3),\pm1,\pm2\rbrace \end{gathered}`

Final Answer

The answer is OPTION C