Question

I need a bit of help with these TWO questions Question b

Answer 1

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the equations

`\begin{gathered} 4x+y=10 \\ 5x=19+2y \end{gathered}`

STEP 2: solve the equations algebraically

`\begin{gathered} \mathrm{Substitute\:}x=(10-y)/(4) \\ \begin{bmatrix}5\cdot (10-y)/(4)=19+2y\end{bmatrix} \\ (50-5y)/(4)=19+2y \\ 50-5y=76+8y \\ 50-76=8y+5y \\ -26=13y \\ y=(-26)/(13) \\ y=-2 \\ \end{gathered}`

STEP 3: Solve for x

`\begin{gathered} \mathrm{For\:}x=(10-y)/(4) \\ \mathrm{Substitute\:}y=-2 \\ x=(10-\left(-2\right))/(4) \\ x=3 \end{gathered}`

Hence, the values are given as:

x = 3

y = -2