The angels 60, a, and 55 are supplementary, meaning they add up to 180 degrees.
Therefore we have
![60+a+55=180](https://img.qammunity.org/2023/formulas/mathematics/college/b70y61dn6jsf85i50qu0l1564f8a3gqlwu.png)
Solving for a gives us
![\textcolor{#FF7968}{a=65.}](https://img.qammunity.org/2023/formulas/mathematics/college/2sjodce9i2fohh58eaa5uf5vo1c8ergsal.png)
Now, we know that the sum of angles in a triangle is 180 degrees; therefore,
![a+b+90=180](https://img.qammunity.org/2023/formulas/mathematics/college/95b05lx5qm33htvkf7fbj1uhqyv8a52lsr.png)
since a = 65, we have
![65+b+90=180](https://img.qammunity.org/2023/formulas/mathematics/college/m49e58ao44x0ceqi6zbwn1d5naspxmjfxv.png)
solving for b gives us
![\textcolor{#FF7968}{b=25.}](https://img.qammunity.org/2023/formulas/mathematics/college/elayng9o51flsziv8uz2r320g311sf4zvc.png)
The angle c is opposite the angle b; therefore, it is
![\textcolor{#FF7968}{c=25.}](https://img.qammunity.org/2023/formulas/mathematics/college/j3slvpz98l3vbtidr4r727zhxrpjb6j15c.png)
Angles d and 15 are complementary meaning they add up to 90; therefore, we have
![15+d=90](https://img.qammunity.org/2023/formulas/mathematics/college/zm8wfqbdxwlv88yqnogw8wtedy1ex68n23.png)
![\textcolor{#FF7968}{\therefore d=75}](https://img.qammunity.org/2023/formulas/mathematics/college/5so4xjo0oiv0hl6uv83yb1rcw39jzx2eer.png)