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Write a quadratic function whose graph passes through (4,-7) and has a vertex of (1,6) what does Y=

User Sjoseph
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write a quadratic function whose graph passes through (4,-7) and has a vertex of (1,6)

REmember that

The equation of a vertical parabola in vertex form is equal to

y=a(x-h)^2+k

where

(h,k) is the vertex

a is the leading coefficient

substitute the given values

(h,k)=(1,6)

y=a(x-1)^2+6

Find the value of a

we have the point (4,-7)

so

For x=4

y=-7

substitute

-7=a(4-1)^2+6

-7=a(9)+6

solve for a

9a=-7-6

9a=-13

a=-13/9

therefore

y=(-13/9)(x-1)^2+6

User Jan Tajovsky
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