Answer:
-0.144 m
Step-by-step explanation:
From the question,
α = Δh/(h₁Δt).................... Equation 1
Where α = coefficient of linear expansivity of iron, Δh = change in height, h₁ = initial height, Δt = change in temperature.
make Δh the subject of the equation
Δh = α(h₁Δt)..................... Equation 2
Given: α = 1.2×10⁻⁵/°C, h₁ = 500 m,
Δt = (t₂-t₁) Where t₂ and t₁ = Final and initial temperature respectively.
Δt = (1-25) = -24 °C
Substitute these values into equation 2
Δh = 1.2×10⁻⁵[500×(-24)]
Δh = 1.2×10⁻⁵(-12000)
Δh = -0.144 m