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Evaluate f(×) for the given values for x.

User Parker
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The given function f(x) is given to be:


f(x)=(x+3)^2

At point x = -5, we substitute for x in the given function, thus we have:


\begin{gathered} f(x)=(x+3)^2 \\ f(-5)=(-5+3)^2 \\ f(-5)=(-2)^2 \\ f(-5)=4 \end{gathered}

Hence, the evaluation of f(x) at x = -5 is 4

User Abdul Rasheed
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