Answer:
Concentration of 1.798 M of the potassium ion.
Step-by-step explanation:
1st) It is necessary to write the dissociation equation of K2CO3:
![K_2CO_3\rightarrow2K^++CO_3^(-2)](https://img.qammunity.org/2023/formulas/chemistry/college/od693phunauy57dvke4bao2ccpox7krab5.png)
2nd) In the dissociation equation of K2CO3, we can see that from 1 mole of K2CO3, 2 moles of potassium ion (K+) are formed, so from 0.899 M K2CO3 solution we will have:
2 x 0.899M = 1.798 M
a concentration of 1.798 M of the potassium ion.