Equation of a shaded region
We have the body line described by the equation:
![y=-(8x)/(3)-1](https://img.qammunity.org/2023/formulas/mathematics/college/sqs5wfc13v1uid26xrq8vmnzxcdc5lrh8o.png)
For the shaded region we have two possible cases:
![\begin{gathered} 1.\text{ }y\leq-(8x)/(3)-1 \\ 2.\text{ }y\ge-(8x)/(3)-1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/21qcfgfby63l1zu1jnu4l0dx9j1ayjupnl.png)
We select any point from the shaded region. This time we are going to work with the point (-3, -3), that is when x = -3 and y = -3.
We are going to replace it in the equation and after that we are going to complete it using one of the signs ≥ or ≤ using the one that gives as a true inequality:
![\begin{gathered} y??_{}-(8x)/(3)-1 \\ -3??_{}-(8\cdot(-3))/(3)-1 \\ -3??_{}8-1 \\ -3??_{}7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5e3n6de2inamm5hnl1ts9u80by630eqgnz.png)
Since -3 is minor than 7, the sign we use is ≤:
![-3\leq7](https://img.qammunity.org/2023/formulas/mathematics/college/olhwzlxy7q2kk0o3hbpmkty309vrokeprb.png)
Then, we have this time the case 1.
Answer: The inequality that describes the shaded region is y ≤ -8x/3 -1
![y\leq-(8x)/(3)-1](https://img.qammunity.org/2023/formulas/mathematics/college/zp7ulklkod4ubatn0ted1tnty9886eoxnk.png)