Recall that to calculate the amount after t years that is compounded continously at a intereset rate r of an investment of a principal P is given by the formula
![A=Pe^(rt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/5drqeoscjn6fncl992j2z04p3erm9eojdf.png)
In this case, the initial amount is P. Since we want to calculate the value of t for which A is exactly 2*P we have the equation
![2P=Pe^(rt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/692nb9a48dd7ngrjvmz1ifg5ei2qvciv2h.png)
we know that r=0.049 and we want to solve this equation for t. WE start by dividing both sides by P. So we get
![2=e^(0.049t)](https://img.qammunity.org/2023/formulas/mathematics/college/pbrhqm2u8xmtiixbjefw833s8ihr1zh0o9.png)
If we apply the natural logarithm on both sides, we get
![0.049t=\ln (2)](https://img.qammunity.org/2023/formulas/mathematics/college/hso6ljybstjbfcbizel6l0k8v7568setm8.png)
so if we divide both sides by 0.049, we get
![t=(\ln (2))/(0.049)=14.14145860](https://img.qammunity.org/2023/formulas/mathematics/college/nwdn9nbcyzqva7wwnfp3z9611nivmded38.png)
which rounded to the nearest tenth of a year is 14.1 years