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How many moles are in 7.89 x 10^28 atoms of Nitrogen?

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Answer:

• From avogadro's number:


{ \tt{6.02 * {10}^(23) \: atoms = 1 \: mole}} \\ { \tt{7.89 * {10}^(28) \: atoms = (\frac{7.89 * {10}^(28) }{6.02 * {10}^(23) } )}} \\ \\ = { \tt{1.31 * {10}^(5) \: moles }}

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