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–5 + 2y = 5 5 ×– 2y = -5 o One Solution O Infinitely Many Solutions O No Solutions

–5 + 2y = 5 5 ×– 2y = -5 o One Solution O Infinitely Many Solutions O No Solutions
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–5 + 2y = 5 5 ×– 2y = -5 o One Solution O Infinitely Many Solutions O No Solutions

User Martinatime
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1 Answer

2 votes

The equations are,

–5 + 2y = 5, 5 ×– 2y = -5

User Pellet
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