The slope of a line that passes through the points (x1, y1) and (x2, y2) is computed as follows:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
The point-slope form of a line is:
![y-y_1=m(x-x_1_{})](https://img.qammunity.org/2023/formulas/mathematics/college/dl1cfwqxy56v41xyrqqpfbssz83xee851z.png)
7) The line passes through (0,-2) and (3,2)
Slope:
![m=(2-(-2))/(3-0)=(4)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/2u92m83e7h2hry4jikbpd26oupbfumjw7q.png)
Equation:
y - 2 = 4/3(x - 3)
8) The line passes through (0,5) and (4,3)
Slope:
![m=(3-5)/(4-0)=-(2)/(4)=-(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/2jl4whi9m8bgpr0gdxjhozj33rm0wd59ll.png)
Equation:
y - 3 = -1/2(x - 4)
9) this line is parallel to the y-axis, then it has the form:
x = constant
In this case, the equation is:
x = 1