Question

Hi, can you help me to solve this exercise please!!!

Answer 1

Given:

`\sin \theta=(12)/(13)`

For given interval:

`\begin{gathered} 90^(\circ)<\theta>180^(\circ) \\ \sin \theta=(12)/(13) \\ \theta=\sin ^(-1)((12)/(13)) \\ \text{for interval} \\ \theta=180-\sin ^(-1)((12)/(13)) \\ \theta=180-67.3801 \\ \theta=112.619 \end{gathered}`

so

`\begin{gathered} =\cos \theta \\ =\cos (112.619) \\ =-0.3846 \end{gathered}`