Question

A car of 1000 kg car experiences a net force of 9500 N while decelerating from 300.0 cm/s to200 cm/s. How far does it travel while slowing down?None of the above18.5mO 0.263mO 20.2 mO 21.9 m

Answer 1

Given:

Mass of car, m = 1000 kg

Net force = 9500 N

Change in velocity = 300 cm/s to 200 cm/s

Let's find the distance travelled while slowing down.

Apply the formula:

`v^2=u^2+2as`

Where:

v is the final velocity = 200 cm/s

u is the initial velocity = 300 cm/s

a is the acceleration

s is the distance

To find the accel