89.8k views
0 votes
Please help me solve the equation on the interval shown in the picture. Must show work.

Please help me solve the equation on the interval shown in the picture. Must show-example-1
User Upment
by
8.0k points

1 Answer

3 votes

Answer:

Given that,


1-\sin\theta=0\text{ for an interval of }\theta\text{ is 0}\leq\theta\leq2\pi

On solving this we get,


\sin\theta=1

we get,


\theta=(\pi)/(2)

Since the period of sin theta is 2 pi.

The solution of the given equation is,


\theta=(\pi)/(2)
User Omry Atia
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories