Question

find an equation of the line having the given slope and containing the given point . slope 3/4; through (-12,4) Type answer in slope intercept form .

Answer 1

Ok, so

Remember that if we got the slope of the line and a point of it, we could use the following formula:

`y=y_1+m(x-x_1)`

Where (x1,y1) is a point and m is the slope.

If we replace our values:

`\begin{gathered} y=4+(3)/(4)(x-(-12)) \\ \\ y=4+(3)/(4)(x+12) \\ \\ y=4+(3)/(4)x+(36)/(9) \\ \\ y=4+(3)/(4)x+4 \\ \\ y=(3)/(4)x+8 \end{gathered}`

Therefore, the equation of this line will be:

y=3/4x+8