If Dionte creates a list, it will be (3*n, 9*n) where "n" is the number of books, then, we have the pattern:
![(3n,9n)\quad n\in\mathbb{N}](https://img.qammunity.org/2023/formulas/mathematics/high-school/dg3mj1vhgu5lrrlxi2dqon0hrpmmtbrm5j.png)
But how do discover which one should be on the list? See that the first coordinate is divisible by 3, if we divided it by 3 we have just "n", if we do divide the second coordinate by 9 we have just "n" as well. Then we have to divide by three the first coordinate and by 9 the second one, after that they must be the same! if they are the same it's correct.
a)
![(6,27)_{}](https://img.qammunity.org/2023/formulas/mathematics/high-school/brjvewl6ktgmkn24tduytkofxoytiz40v7.png)
Let's do our logic, divide by 3 and the other by 9
![((6)/(3),(27)/(9))=(2,3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/ra24s2zpfjpy8ptsx6z6mgjhuogj7sv66g.png)
As we can see it's different, so it couldn't be on Dionte's list.
b)
Doing the same thing
![((12)/(3),(36)/(9))=(4,4)](https://img.qammunity.org/2023/formulas/mathematics/high-school/cjvpk2zzkgqfjmka8g27gwauufgk18ip0o.png)
The result is (4,4), two equal numbers, then it could be on Dionte's list.
c)
![((15)/(3),(45)/(9))=(5,5)](https://img.qammunity.org/2023/formulas/mathematics/high-school/g6mbxylbn5qrffdo8othmwuaceo3tg2wz6.png)
The result is (5,5), two equal numbers, then it could be on Dionte's list.
d)
![((18)/(3),(54)/(9))=(6,6)](https://img.qammunity.org/2023/formulas/mathematics/high-school/mqm24482w87rpx5zwlozh7hfvmx4dlkd77.png)
The result is (6,6), two equal numbers, then it could be on Dionte's list.
e)
![((24)/(3),(81)/(9))=(8,9)](https://img.qammunity.org/2023/formulas/mathematics/high-school/wfduyo3agjvamv67uspkt49zt9e350298v.png)
Here we have a different result again, then it couldn't be on Dionte's list.