We have to calculate the midpoint for each segment.
To do that we have to calculate the average for the coordinates of each point.
1) For AB, we have A = (-5,8) and B = (-5,6).
We can then calculate the midpoint coordinates as:
![M_(AB)=((x_A+x_B)/(2),(y_A+y_B)/(2))=((-5+(-5))/(2),(8+6)/(2))=(-(10)/(2),(14)/(2))=(-5,7)](https://img.qammunity.org/2023/formulas/mathematics/high-school/a4z4aldfir5uqsigfj4d6qbnjsg25zp2v4.png)
2) For BC we have B = (-5,6) and C = (-2,6).
The midpoint will be:
![M_(BC)=((-5+(-2))/(2),(6+6)/(2))=((-7)/(2),(12)/(2))=(-(7)/(2),6)](https://img.qammunity.org/2023/formulas/mathematics/high-school/x7gcq87jb7l046uj8wgttk6q10pr1j8mya.png)
3) For CD we have C = (-2,6) and D = (2,3).
The midpoint will be:
![M_(CD)=((-2+2)/(2),(6+3)/(2))=((0)/(2),(9)/(2))=(0,(9)/(2))](https://img.qammunity.org/2023/formulas/mathematics/high-school/t0l0ht7dkg6ftfpy2tuk23teccc35k89rn.png)
4) For DE we have D = (2,3) and E = (2,-1).
The midpoint will be:
![M_(DE)=((2+2)/(2),(3+(-1))/(2))=((4)/(2),(2)/(2))=(2,1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/x8vuaqkolld8lrad22or7xp53jae6652qq.png)
5) For EF we have E = (2,-1) and F = (6,0).
The midpoint will be:
![M_(EF)=((2+6)/(2),(-1+0)/(2))=((8)/(2),-(1)/(2))=(4,-(1)/(2))](https://img.qammunity.org/2023/formulas/mathematics/high-school/8u8dkyule90s8e7hur74o94ddzgfj5ymsz.png)
Answer:
AB = (-5,7)
BC = (-7/2,6)
CD = (0,9/2)
DE = (2,1)
EF = (4,-1/2)