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Two consecutive even numbers whoes sum is 126

User Barakcaf
by
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1 Answer

4 votes

Since an even number can be represented as:


2n

With n a natural number, and the next even number is:


2n+2

Set the sum of both even numbers equal to 126:


(2n)+(2n+2)=126

Solve for n:


\begin{gathered} \Rightarrow2n+2n+2=126 \\ \Rightarrow4n+2=126 \\ \Rightarrow4n=126-2 \\ \Rightarrow4n=124 \\ \Rightarrow n=(124)/(4) \\ \Rightarrow n=31 \end{gathered}

Substitute back n=31 into the expressions for the even numbers to find them:


\begin{gathered} 2(31)=62 \\ 2(31)+2=64 \end{gathered}

Therefore, the two consecutive even numbers whose sum is 126, are 62 and 64.

User Linlin
by
9.2k points

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