Given:
On first day, the number of adult tickets sold, p=9.
On first day, the number of student tickets sold, q=3.
The total price of tickets sold on first day, t=$120.
On second day, the number of adult tickets sold, m=1.
On second day, the number of student tickets sold, n=1.
The total price of tickets sold on second day, T=$22.
Let x be the price of one adult ticket and y be the price of one student ticket.
Hence, the expression for the total price of tickets sold on first day is,

The expression for the total price of tickets sold on second day is,

Now, multiply equation (2) by 3.

Subtract equation (3) from equation (1) and solve for x.

So, x=9.
Now, substitute x=9 in equation (2) and solve for y.

Therefore, the price of each adult ticket is $9 and the price of each student ticket is $13.