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The area of the rectangle is 3/4 square feet. If A:L×H, what is the length of a rectangle?

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A rectangular box is in the shape of cuboid.

Volume of cuboid = Length x Breadth x Height.

It is given that the dimension of the mail box are


4(1)/(2)feet\text{ by }2\text{ f}eet\text{ by 2}(1)/(2)feet

i.e.


\begin{gathered} \text{Length}=4(1)/(2) \\ \text{Breadth}=2 \\ \text{Height}=2(1)/(2) \end{gathered}

Substitute the value in the expression of volume.


\begin{gathered} \text{Volume of mail box=Length}* Height\text{ }*\text{Breadth} \\ \text{Volume of mail box=4}(1)/(2)*2(1)/(2)*2 \\ \text{Volume of mail box=}(9)/(2)*(5)/(2)*2 \\ \text{Volume of mail box=}(90)/(4) \\ \text{Volume of mail box=22.5 f}eet^3 \end{gathered}

Answer: The volume of mail box is 22.5 feet³

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