1 Answer

Charanjeet Kaur · Answer 1 · 2023-05-20T22:57:55+0000

Given that the bag contains three coloured tiles as,

3 Red, 6 Green and 3 Blue.

A tile is randomly selected, total ways are

$\begin{gathered} =^3C_1+^6C_1+^3C_1 \\ =3+6+3 \\ =21 \end{gathered}$

selecting a green will be given as ,

$\begin{gathered} =^6C_1 \\ =6 \end{gathered}$

So, the required probability is given as,

$\begin{gathered} P=(6)/(21) \\ =0.2857 \end{gathered}$

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