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5 votes
I have a star question practice I need help on

User Leopinzon
by
6.4k points

1 Answer

4 votes

Given that the bag contains three coloured tiles as,

3 Red, 6 Green and 3 Blue.

A tile is randomly selected, total ways are


\begin{gathered} =^3C_1+^6C_1+^3C_1 \\ =3+6+3 \\ =21 \end{gathered}

selecting a green will be given as ,


\begin{gathered} =^6C_1 \\ =6 \end{gathered}

So, the required probability is given as,


\begin{gathered} P=(6)/(21) \\ =0.2857 \end{gathered}

User Charanjeet Kaur
by
7.5k points
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