Given the equation:
![-4x+y-38=0](https://img.qammunity.org/2023/formulas/mathematics/college/l8uy2zs5jnd7n1f0shax4ffp4je6elqwbs.png)
We will find the point on the line with the x-coordinate x = -8
So, substitute with x = -8, and solve the equation to find y
So, when x = -8
![\begin{gathered} (-4)\cdot(-8)+y-38=0 \\ 32+y-38=0 \\ y-6=0 \\ y=6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5w7bt8j3feuhnrz171uqysxz1kj6qg6210.png)
So, the point will be (x,y) = (-8, 6)
The graph of the point on the line will be as follows: