Question

A diver exhales a bubble with a volume of 250 mL at a pressure of 2.42 atm and a temperature of 15 °C. What is the volume of the bubble when it reachesthe surface where the pressure is 0.95 atm and the temperature is 28 °C? Show all your workYour Answer

Answer 1

The volume of the bubble when it reaches the surface is 1,186.2mL.

Step-by-step explanation:

The data of the initial state of the bubble is:

• V1= 250mL

,

• P1= 2.42atm

,

• T1= 15°C

The data of the final state of the bubble is:

• V2= this is what we are going to calculate.

,

• P2= 0.95atm

,

• T2=28°C

Now, with the ideal gas formula we can calculate the final volume of the bubble:

`\begin{gathered} (P_1*V_1)/(T_1)=(P_2*V_2)/(T_2) \\ (2.42atm*250mL)/(15°C)=(0.95atm*V_2)/(28°C) \\ 40.33(atm*mL)/(°C)=0.034(atm)/(°C)*V_2 \\ (40.33(atm*mL)/(°C))/(0.034(atm)/(°C))=V_2 \\ 1,186.2mL=V_2 \end{gathered}`

So, the volume of the bubble when it reaches the surface is 1,186.2mL.