Question

Find VW to the nearest tenth using Pythagorean Theorem.41(1,3)OW (6,1)

Answer 1

From the graph v = (1,3) and w = ( 6 , -1)

the distance vw = d

`\begin{gathered} d=\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ ^{} \end{gathered}`
`d=\sqrt[]{(6-1)^2+(-1-3)^2}=\sqrt[]{5^2+4^2}=\sqrt[]{25+16}=\sqrt[]{41}`
`\sqrt[]{41}=6.4`

So, vw = 6.4 to the nearest tenth

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