Consecutive integers differ by 1.
Let x represent the first integer.
The second integer would be x + 1
The third integer would be x + 1 + 1 = x + 2
The fourth integer would be x + 1 + 1 + 1 = x + 3
Given that 5 times the third number decreases te second by 41, it means that
5(x + 2) - (x + 1) = 41
5x + 10 - x - 1 = 41
5x - x + 10 - 1 = 41
4x + 9 = 41
4x = 32
x = 32/4
x = 8
The numbers are 8, 8 + 1, 8 + 2 and 8 + 3
The numbers are 8, 9, 10 and 11