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9 votes
9 votes
A 16 foot ladder is leaning against a wall with the base 4 feet from the wall. How high does the ladder hit the wall?

User Remick
by
2.9k points

2 Answers

20 votes
20 votes

Answer:


x = 15.49

Explanation:

To solve this problem is necessary to use the pythagorean theorem:

According to this diagram, the length of the ladder would be the hypotenuse and the distance between the base and the wall would be one of the legs of the triangle, to find the other leg, use the pythagorean theorem:


x = \sqrt{ {16}^(2) - {4}^(2) } \\ x = √(240) \\ x = 15.49

The ladder hits the wall at 15:49 feet.

A 16 foot ladder is leaning against a wall with the base 4 feet from the wall. How-example-1
User JerryWho
by
3.2k points
13 votes
13 votes

Answer:

15.49

Explanation:

The pythagorean theorem

4^2 + B^2 = 16^2

16 + B^2 = 256

16 + 240 = 265

Sqrt240 = 15.49

User Egidra
by
2.6k points