173k views
3 votes
Let the universal Set be s. Let A and B are subsets of S. Set contains 90 elements and Set B contains 99 elements. Set A and B have 21 elements in common. If there are 24 elements that are in S but not in A nor B, how many elements are in S ?

1 Answer

3 votes

Given

Set A contains = 90 elements

Set B contains = 99 elements

A and B contains = 21 elements

Find

number of elements in Set S

Step-by-step explanation

As we know


n(A\cup B)=n(A)+n(B)-n(A\cap B)

so,


n(A\cup B)=90+99-21=168

Total elements in S = elements in A or B + elements not in A or B

so,


168+24=192

Final Answer

Total elements in S = 192

User Gsbabil
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories