ANSWER:
The IQR is 7, and the range is 11
Explanation:
The first thing is to identify the extremes of the picture, which is the minimum value and the maximum value
![\begin{gathered} V_(\min )=6 \\ V_(\max )=17 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/v1i72ba1a9wdife6gbefqdzw5qbo1kh4fs.png)
We calculate the median of the data, which is the number of the half:
![m=(11+12)/(2)=11.5](https://img.qammunity.org/2023/formulas/mathematics/college/jykxbdqwn2ll4ph3fhjs7h6n7ma3yjeob8.png)
We calculate the median of Q1 (6 - 11.5) and the median of Q3 (11.5 - 17)
![\begin{gathered} m_(Q1)=8 \\ m_(Q2)=15 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hthzz5ptyayu5uj81jhjhhsb46l1n35c0t.png)
The IQR is the difference between Q3 and Q1 medians, therefore
![\begin{gathered} \text{IQR}=m_(Q3)-m_(Q1)=15-8 \\ \text{IQR = 7} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9zeifcvpfl2u1q6m6dyd8t2xfi7enq1k9a.png)
The range is the difference between the minimum and maximum value, therefore
![R=V_(\max )-V_(\min )=17-6=11](https://img.qammunity.org/2023/formulas/mathematics/college/s92lvej9wcf7qtnzy1cl3w33u01nmj6im1.png)