Given that the height of a candle (in centimeter) is a linear function of time (in hour) it has been burning.
Let at time t, the height of the candle be h
Since h is a linear function of t, let us assume
![h=at+b](https://img.qammunity.org/2023/formulas/mathematics/college/fjv03kc9ih9h448wxlkdoeoj6vvd133qd0.png)
After 6 hours of burning, the candle has a height of 19.4 centimeters.
After 20 hours of burning, its height is 11 centimeters.
So, the line representing h passes through the points (6,19.4) and (20,11)
Using two-point formula
![\begin{gathered} (h-11)/(19.4-11)=(t-20)/(6-20) \\ (h-11)/(8.4)=(t-20)/(-14) \\ h=-(3)/(5)t+23 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jnns78e1y4caj7tixp2ugzfu2sb34i6nj9.png)
So, the height of the candle is
![h=-(3)/(5)t+23](https://img.qammunity.org/2023/formulas/mathematics/college/2m3u3ud2k8y1vpvssbrqmi7z1g26pwjwtv.png)
Now, putting t=8, it gives
![\begin{gathered} h=23-(3)/(5)*8 \\ =23-(24)/(5) \\ =(115-24)/(5) \\ =(91)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/sqdom3dzc0059zybxrh392yu2ntb16y9qq.png)
So, after 8 hours, the height of the candle is 18.2 centimeters.