Question

**Given p(x) = 23=23 - 6x^2 - 5x - 14, determinewhether (x - 7) is a factor of p(x).

Answer 1

Given:

`p(x)=x^3-6x^2-5x-14`

Factor of (x-7) is:

`\begin{gathered} =(p(x))/(x-7) \\ =(x^3-6x^2-5x-14)/(x-7) \end{gathered}`

so factor of (x-7) is:

`\begin{gathered} p(x)=x^3-6x^2-5x-14 \\ =(x-7)(x^2+x+2) \end{gathered}`