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What is the answer for (12y¹¹ /6 y⁴)⁻⁴

User Nsanders
by
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1 Answer

2 votes


(1)/(16y^(28))

STEP - BY - STEP EXPLANATION

What to find?

The solution to the system of equation.

Given:

(12y¹¹ /6 y⁴)⁻⁴


((12y^(11))/(6y^4))^(-4)

To solve the given problem, we will follow the steps below:

Step 1

Recall the law of indices that is applicable.

That is;


\begin{gathered} \frac{a^3^{}^{}^{}}{a^2}=a^(3-2) \\ \\ a^(-2)=(1)/(a^2) \end{gathered}

Step 2

Apply the first law on the given expression.


\begin{gathered} (2y^(11-4))^(-4) \\ \\ (2y^7)^(-4) \end{gathered}

Step 3

Apply the second law to the above.


=(1)/((2y^7)^4)
=(1)/(16y^(28))

Therefore,


((12y^(11))/(6y^4))^(-4)=(1)/(16y^(28))

User Jfriedman
by
4.1k points