SOLUTION
The eccentricity is the measure of how much the ellipse deviates from a circle.
The eccentricity of an ellipse which is not a circle is greater than zero but less than 1.
For an ellipse, the eccentricity is giving as
![\frac{\sqrt[]{a^2-b^2}}{a}](https://img.qammunity.org/2023/formulas/mathematics/college/4fcl3ul6ou09i7194hf30ned5usakkjl11.png)
where
![\begin{gathered} a^2=50,a=\sqrt[]{50}=5\sqrt[]{2} \\ b^2=9,b=\sqrt[]{9}=3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nio47srrnr3d7y9gpcrv5ttbl53r494dr9.png)
Substitute the value into the formula we have
![\begin{gathered} \frac{\sqrt[]{50-9}}{5\sqrt[]{2}} \\ \text{Then } \\ \frac{\sqrt[]{41}}{5\sqrt[]{2}} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nd16cubqwnywrcfciq2ek959hklhs19xim.png)
Then rationalize the expression in the last line
![\frac{\sqrt[]{41}*\sqrt[]{2}}{5\sqrt[]{2}*\sqrt[]{2}}=\frac{\sqrt[]{82}}{10}=0.9055](https://img.qammunity.org/2023/formulas/mathematics/college/gc2tq3eltzzwfn908kocvs8cxarhn4ofpp.png)
Hence the eccentricity of the ellipse is approximately 0.91
Since the value of a is much larger than b, then it indicates that the ellipse is
More Elongated than circular.