Question

1. Car traveling at 34.6m/s has an acceleration of -3.4m/s². What is the car'svelocity after 3s?#1

Answer 1

We have the next data

vi=initial velocity=34.6 m/s

a=acceleration=-3.5 m/s^2

t=time=3s

we need to find the final velocity (vf)

We will use the next formula

`a=(vf-vi)/(t)`

then we substitute the data

`-3.4=(vf-34.6)/(3)`

then we isolate the vf

`vf=-3.4(3)+34.6`
`vf=-10.2+34.6`

`vf=24.4\text{ m/s}`

the velocity of the car after 3 seconds is 24.4 m/s