The two points on a coordinate plane are given as [-6,3] and [-6,0]. The distance between the two points can be calculated using the Pythagoras' theorem which states;
AC^2 = AB^2 + BC^2
The two points are given as [x1, y1] and [x2, y2]
In the Pythagorean formula, the line AC is the hypotenuse and it connects the vertical (y-axis) and the horizontal (x-axis).
To find the horizontal we use, [x2 - x1] and the vertical is derived as [y2 - y1].
AC is the distance between both and applying the Pythagorean theorem, you now have;
d^2 = [x2 - x1]^2 + [y2 - y1]^2
d^2 = [-6 - (-6)]^2 + [0 - 3]^2
d^2 = [0]^2 + [- 3]^2
d^2 = 0 + 9
Add the square root to both sides to eliminate the square on the left side of the equation
d = √9
d = 3
Therefore, the distance between both points is 3