Question

I need help with this i dont understan it well

Answer 1

First we need to calculate the areas

The area of a triangle is

`A_T=2(b* h)/(2)=b* h`

b=3 in

h=6 in

we substitute the values

`A_T=3*(6)=18in^2`

the area combined of the two triangles is 18 in^2

the area of the trapezoid

`A_(Tr)=((B+b)\cdot h)/(2)`

where

B=12in

b=6in

h=6 in

we substitute the values

`A_(Tr)=((12+6)\cdot6)/(2)=54in^2`

so the ratio is

54:18