Austin has two options:
Option 1: Pay $40 for unlimited rides
Option 2: pay $16 plus $2 per ride
For the two options to end up costing the same amount, the second option needs to end up being $40, because the payment in the first option is already fixed to $40.
That answers the first question:
What is the cost? $40
Now we need to find how many rides are needed for the second option to cost $40.
We will call the number of rides "x", and thus, since in the 2nd option there is an admission cost of 16 and a cost of $2 per ride, the expression that represents the cost is in option 2 is:
![16+2x](https://img.qammunity.org/2023/formulas/mathematics/college/qtq3bnqthghoiyy092zjxp55fpsy472asp.png)
And since we know that the cost has to be $40 to be equal to the cost of option 1:
![16+2x=40](https://img.qammunity.org/2023/formulas/mathematics/college/p42inxmf25zejxg7gkmk6udsc023b637w0.png)
And now we solve this equation for the number of rides x.
First, Subtract 16 to both sides of the equation:
![16-16+2x=40-16](https://img.qammunity.org/2023/formulas/mathematics/college/2cqj2hfa05gwu6qki9mbiuhn423mr8mucv.png)
On the left side, 16-16 cancel each other, and on the right side 40-16 is 24, thus:
![2x=24](https://img.qammunity.org/2023/formulas/mathematics/high-school/japyjzl1n7f5wtmvrberi11satw3h8kvrr.png)
Finally, divide both sides of the equation by 2 to find the value of x:
![\begin{gathered} (2x)/(2)=(24)/(2) \\ \\ x=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4dbm7kjyjnggc93rzwth68ia4cej5dd7l2.png)
The number of rides for the second option to be equal in cost to the first option is 12 rides.
Answer:
The cost is $40 and the number of rides is 12.