So,
Given the function:
![f(x)=(4)/(x^2-36)](https://img.qammunity.org/2023/formulas/mathematics/college/b00htfbjn7pot7rhjesi1yiz3lamf10g1l.png)
To check if the function is continuous in the entire number real line, we need to analyze the restrictions in the domain.
As you can notice, the denominator of a rational function can't be zero, so:
![x^2-36\\e0](https://img.qammunity.org/2023/formulas/mathematics/college/ivlmh0zk95a1axsvd32c1vv2vqv9j7s4lt.png)
We're going to find the values of x such that:
![x^2-36=0](https://img.qammunity.org/2023/formulas/mathematics/college/hkbp9s79q1jibhk54a5jem4wltns6cg5rb.png)
This is:
![\begin{gathered} x^2=36 \\ x=\pm6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8bobsgv29lb5lqw875crveydrnaqpqfqmh.png)
As you can see, "x" can't take the values of 6 and -6. If that happens, the function is not defined. Thus, the function is not continuous on the entire real number line.