1 Answer

Nik Chankov · Answer 1 · 2023-03-23T05:29:08+0000

The apparent mass m is related to the actual mass m_0 by:

$m=\frac{m_0}{\sqrt{1-(v^2)/(c^2)}}$

Isolate v:

$v=c\sqrt{1-\left((m_0)/(m)\right)^2}$

Replace m=1.0311m_0:

$v=c\sqrt{1-\left((m_0)/(1.0311m_0)\right)^2}=0.24375...c\approx7.3*10^6(m)/(s)$

Therefore, the speed of the object is approximately 7.3*10^6 m/s.

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