Question

How many milliliters of 10.5 M HCl(aq) are needed to prepare 160.0 mL of 1.00 M HCl(aq)?V=mL

Answer 1

So,

We could use the following equation:

M1 and M2 represent the initial and final concentrations and V1 and V2 represent the initial and final volumes respectively.

Replacing our values:

Therefore, 15.2380mL are required.