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Using the polynomial remainder theoremP(x) = x^2-9x^3-5x^2-4x+5 divided by x + 3

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The given polynomial is

x^2 - 9x^3 - 5x^2 - 4x + 5

By simplifying it, it becomes

- 9x^3 + x^2 - 5x^2 - 4x + 5

- 9x^3 - 4x^2 - 4x + 5

We want to divide it by x + 3. To use the remainder theorem, we would substitute x = - 3 into the polynomial to find the remainder, r. We have

r = p(- 3) = -9(-3)^3 - 4(-3)^2 - 4(-3) + 5

243 - 36 + 12 + 5

r = 224

Thus, the remainder when P(x) = x^2-9x^3-5x^2-4x+5 is divided by x + 3 is 224

P(-3) = 224

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